${{\mathit h}_{{{1}}}{(1595)}}$ $I^G(J^{PC})$ = $0^-(1^{+ -})$
Seen in a partial-wave analysis of the ${{\mathit \omega}}{{\mathit \eta}}$ system produced in the reaction ${{\mathit \pi}^{-}}$ ${{\mathit p}}$ $\rightarrow$ ${{\mathit \omega}}{{\mathit \eta}}{{\mathit n}}$ at 18$~$GeV/$\mathit c$.