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CONSTRAINED FIT INFORMATION show precise values?

An overall fit to 14 branching ratios uses 18 measurements to determine 9 parameters. The overall fit has a $\chi {}^{2}$ = 11.7 for 9 degrees of freedom.     The following off-diagonal array elements are the correlation coefficients <$\mathit \delta $p$_{i}\delta $p$_{j}$> $/$ ($\mathit \delta $p$_{i}\cdot{}\delta $p$_{j}$), in percent, from the fit to parameters ${{\mathit p}_{{{i}}}}$, including the branching fractions, $\mathit x_{i}$ = $\Gamma _{i}$ $/$ $\Gamma _{total}$.

x1  100  x3    100  x16      100  x32        100  x33          100  x43            100  x58              100  x66                100  x67                  100     x1   x3   x16   x32   x33   x43   x58   x66   x67

Mode  Fraction (Γi / Γ) Scale factor Γ1  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit J / \psi}{(1S)}}{{\mathit \Lambda}}$  ($3.0$ $\pm0.8$) $ \times 10^{-4}$  Γ3  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit \psi}{(2S)}}{{\mathit \Lambda}}$  ($1.5$ $\pm0.4$) $ \times 10^{-4}$  Γ16  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit J / \psi}}{{\mathit \Xi}^{-}}{{\mathit K}^{+}}$  ($3.6$ $\pm1.1$) $ \times 10^{-6}$  Γ32  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit \Lambda}_{{{c}}}^{+}}{{\mathit \pi}^{-}}$  ($4.9$ $\pm0.4$) $ \times 10^{-3}$  1.2 Γ33  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit \Lambda}_{{{c}}}^{+}}{{\mathit K}^{-}}$  ($3.56$ $\pm0.28$) $ \times 10^{-4}$  1.2 Γ43  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit \Lambda}_{{{c}}}^{+}}{{\mathit \pi}^{+}}{{\mathit \pi}^{-}}{{\mathit \pi}^{-}}$  ($7.6$ $\pm1.1$) $ \times 10^{-3}$  1.1 Γ58  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit \Lambda}_{{{c}}}^{+}}{{\mathit \ell}^{-}}{{\overline{\mathit \nu}}_{{{{{\mathit \ell}}}}}}$  ($6.2$ ${}^{+1.4}_{-1.3}$) $ \times 10^{-2}$  Γ66  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit p}}{{\mathit \pi}^{-}}$  ($4.6$ $\pm0.8$) $ \times 10^{-6}$  Γ67  ${{\mathit \Lambda}_{{{b}}}^{0}}$ $\rightarrow$ ${{\mathit p}}{{\mathit K}^{-}}$  ($5.5$ $\pm1.0$) $ \times 10^{-6}$

 

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